Vaibhav Sagar
@vbhvsgr
Source: https://stackoverflow.com/questions/583876/how-do-i-check-if-a-directed-graph-is-acyclic
Source: https://stackoverflow.com/questions/583876/how-do-i-check-if-a-directed-graph-is-acyclic
Source: https://upload.wikimedia.org/wikipedia/commons/c/c6/Topological_Ordering.svg
Source: https://stackoverflow.com/questions/583876/how-do-i-check-if-a-directed-graph-is-acyclic
Source: https://upload.wikimedia.org/wikipedia/commons/5/5c/Scc.png
algorithm tarjan is
input: graph G = (V, E)
output: set of strongly connected components (sets of vertices)
index := 0
S := empty array
for each v in V do
if (v.index is undefined) then
strongconnect(v)
end if
end for
function strongconnect(v)
// Set the depth index for v to the smallest unused index
v.index := index
v.lowlink := index
index := index + 1
S.push(v)
v.onStack := true
// Consider successors of v
for each (v, w) in E do
if (w.index is undefined) then
// Successor w has not yet been visited; recurse on it
strongconnect(w)
v.lowlink := min(v.lowlink, w.lowlink)
else if (w.onStack) then
// Successor w is in stack S and hence in the current SCC
// If w is not on stack, then (v, w) is a cross-edge in the DFS tree and must be ignored
// Note: The next line may look odd - but is correct.
// It says w.index not w.lowlink; that is deliberate and from the original paper
v.lowlink := min(v.lowlink, w.index)
end if
end for
// If v is a root node, pop the stack and generate an SCC
if (v.lowlink = v.index) then
start a new strongly connected component
repeat
w := S.pop()
w.onStack := false
add w to current strongly connected component
while (w != v)
output the current strongly connected component
end if
end function